To easily make a new type by taking or picking certain properties from another type in TypeScript, you can use the Pick utility type and pass the name of the type you want to take the properties from as its first type argument, and the properties you need to pick as a string literal union type as its second type argument.
TL;DR
// a simple interface
interface Person {
name: string;
age: number;
salary: number;
}
// make new type by picking the `name`
// and `age` properties from the `Person` interface
// using the `Pick` utility type
type NecessaryDetails = Pick<Person, "name" | "age">;
/*
Content of `NecessaryDetails` type
{
name: string;
age: number;
}
*/
For example, let's say we have an interface called Person with some properties called name having the type of string, age having the type of number, and salary having the type of number like this,
// a simple interface
interface Person {
name: string;
age: number;
salary: number;
}
Now let's say we need to make a new type where we need only the name and age properties from the Person interface, to do that we can use the Pick utility type and pass the Person type as its first type argument and a string literal union type composed of name and age as its second type argument like this,
// a simple interface
interface Person {
name: string;
age: number;
salary: number;
}
// make new type by picking the `name`
// and `age` properties from the `Person` interface
// using the `Pick` utility type
type NecessaryDetails = Pick<Person, "name" | "age">;
/*
Content of `NecessaryDetails` type
{
name: string;
age: number;
}
*/
Now if you hover over the NecessaryDetails type, you can see that the name and age properties are picked from the Person interface and is now available in the NecessaryDetails type.
We have successfully made a new type by taking or picking certain properties from another type in TypeScript. Yay 🥳!
See the above code live in codesandbox.
That's all 😃!
